Electronics - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 4)
4.
If XL= 100 
and R = 100 , then impedance will be
and R = 100 , then impedance will be141.4
14.14
100
200
Discussion:
9 comments Page 1 of 1.
Swat said:
5 years ago
z= √(r^2+Xl^2).
=√(100^2+100^2).
=√20000).
= 141.4.
=√(100^2+100^2).
=√20000).
= 141.4.
Gangadharmanu said:
5 years ago
Z =√(r^2*+l^2).
=√(100*100+100*100).
=√(20000).
=141.4.
=√(100*100+100*100).
=√(20000).
=141.4.
Damilare said:
6 years ago
z = sqrt(r squared +XL squared),
Substituting values,we have;
z = sqrt(20000),
z = 141.4ohms.
Substituting values,we have;
z = sqrt(20000),
z = 141.4ohms.
Rajan said:
6 years ago
Another way to express this is due to Resistor and Inductance current flow are not in the same phase they can be shown as below. Total impedance cannot be plus but use trigonometric equation,
Z^2 = Xl^2 R^2.
Z = sqr(Xl^2 R^2).
Z = sqr(100 * 100 + 100 * 100) = sqr(20000) = 141.4 ohms.
Z^2 = Xl^2 R^2.
Z = sqr(Xl^2 R^2).
Z = sqr(100 * 100 + 100 * 100) = sqr(20000) = 141.4 ohms.
Jyothi said:
7 years ago
R = 100 XL = 100.
Z = sqr(100*100+100*100) = sqr(20000) = 141.4 ohms.
Z = sqr(100*100+100*100) = sqr(20000) = 141.4 ohms.
M.Rizwan Mukati said:
9 years ago
Z = R+jXL.
Then convert it into polar form.
Then convert it into polar form.
Chandan said:
1 decade ago
z=sqrt(R^2+X^2),then z=sqrt(100^2+100^2)
therefore z=sqrt(20000) so implies sqrt(10000*2)
100sqrt(2) i.e100*1.414=141.4
therefore z=sqrt(20000) so implies sqrt(10000*2)
100sqrt(2) i.e100*1.414=141.4
Gautham said:
1 decade ago
If Z=sqrt(R^2+X^2), then Z=sqrt(100^2+100^2)
Therefore, Z=200. Right?
Therefore, Z=200. Right?
Ranjit said:
1 decade ago
Z=sqrt(R2 + X2)
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