# Electronics - RL Circuits - Discussion

Discussion Forum : RL Circuits - General Questions (Q.No. 4)
4.
If XL= 100 and R = 100 , then impedance will be
141.4 14.14 100 200 Explanation:
No answer description is available. Let's discuss.
Discussion:
9 comments Page 1 of 1.

Swat said:   5 years ago
z= √(r^2+Xl^2).
=√(100^2+100^2).
=√20000).
= 141.4.

Z =√(r^2*+l^2).
=√(100*100+100*100).
=√(20000).
=141.4.

Damilare said:   6 years ago
z = sqrt(r squared +XL squared),
Substituting values,we have;
z = sqrt(20000),
z = 141.4ohms.

Rajan said:   6 years ago
Another way to express this is due to Resistor and Inductance current flow are not in the same phase they can be shown as below. Total impedance cannot be plus but use trigonometric equation,

Z^2 = Xl^2 R^2.
Z = sqr(Xl^2 R^2).
Z = sqr(100 * 100 + 100 * 100) = sqr(20000) = 141.4 ohms.

Jyothi said:   7 years ago
R = 100 XL = 100.

Z = sqr(100*100+100*100) = sqr(20000) = 141.4 ohms.

M.Rizwan Mukati said:   9 years ago
Z = R+jXL.

Then convert it into polar form.

z=sqrt(R^2+X^2),then z=sqrt(100^2+100^2)
therefore z=sqrt(20000) so implies sqrt(10000*2)
100sqrt(2) i.e100*1.414=141.4