Electronics - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 4)
4.
If XL= 100 
and R = 100 , then impedance will be
and R = 100 , then impedance will be141.4
14.14
100
200
Discussion:
9 comments Page 1 of 1.
Ranjit said:
1 decade ago
Z=sqrt(R2 + X2)
Gautham said:
1 decade ago
If Z=sqrt(R^2+X^2), then Z=sqrt(100^2+100^2)
Therefore, Z=200. Right?
Therefore, Z=200. Right?
Chandan said:
1 decade ago
z=sqrt(R^2+X^2),then z=sqrt(100^2+100^2)
therefore z=sqrt(20000) so implies sqrt(10000*2)
100sqrt(2) i.e100*1.414=141.4
therefore z=sqrt(20000) so implies sqrt(10000*2)
100sqrt(2) i.e100*1.414=141.4
M.Rizwan Mukati said:
1 decade ago
Z = R+jXL.
Then convert it into polar form.
Then convert it into polar form.
Jyothi said:
10 years ago
R = 100 XL = 100.
Z = sqr(100*100+100*100) = sqr(20000) = 141.4 ohms.
Z = sqr(100*100+100*100) = sqr(20000) = 141.4 ohms.
Rajan said:
9 years ago
Another way to express this is due to Resistor and Inductance current flow are not in the same phase they can be shown as below. Total impedance cannot be plus but use trigonometric equation,
Z^2 = Xl^2 R^2.
Z = sqr(Xl^2 R^2).
Z = sqr(100 * 100 + 100 * 100) = sqr(20000) = 141.4 ohms.
Z^2 = Xl^2 R^2.
Z = sqr(Xl^2 R^2).
Z = sqr(100 * 100 + 100 * 100) = sqr(20000) = 141.4 ohms.
Damilare said:
8 years ago
z = sqrt(r squared +XL squared),
Substituting values,we have;
z = sqrt(20000),
z = 141.4ohms.
Substituting values,we have;
z = sqrt(20000),
z = 141.4ohms.
Gangadharmanu said:
8 years ago
Z =√(r^2*+l^2).
=√(100*100+100*100).
=√(20000).
=141.4.
=√(100*100+100*100).
=√(20000).
=141.4.
Swat said:
7 years ago
z= √(r^2+Xl^2).
=√(100^2+100^2).
=√20000).
= 141.4.
=√(100^2+100^2).
=√20000).
= 141.4.
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