Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 21)
21.
When a parallel 5 k
resistor and a 25 k resistor have a 10 V supply, what is the total power loss?
resistor and a 25 k resistor have a 10 V supply, what is the total power loss?Discussion:
13 comments Page 1 of 2.
Prashant said:
8 years ago
R1 =5K THATS WHY P1 =10*2/5K =20mw (P=V2/R).
R2= 25K THATS WHY P2 = 10*2/25K =4mw.(P=V2/R).
SO,
P = P1+P2 =24mw.
R2= 25K THATS WHY P2 = 10*2/25K =4mw.(P=V2/R).
SO,
P = P1+P2 =24mw.
(1)
Sangeetha said:
1 decade ago
RT=4.166k
V=10
P=V2/RT
P=24mW
V=10
P=V2/RT
P=24mW
Jayasree said:
1 decade ago
How can RT be 4.166 k ?
Since both resistors are parallel to each other RT=2.5 ohms na ?
Since both resistors are parallel to each other RT=2.5 ohms na ?
Mohammad Umair Kabir said:
1 decade ago
Since resistors are parallel so RT will be
1/RT = 1/R1 + 1/R2
1/RT = 1/5 + 1/25 = 6/25
RT = 25/6 or 4.16K
I = V/R = 10/(25/6) = 2.4 mA
So P = VI = (10)(2.4)= 24 mW
1/RT = 1/R1 + 1/R2
1/RT = 1/5 + 1/25 = 6/25
RT = 25/6 or 4.16K
I = V/R = 10/(25/6) = 2.4 mA
So P = VI = (10)(2.4)= 24 mW
Chinnu said:
1 decade ago
Since, r1||r2
rt = 4.166
P = V*V/R
=> P=24.03mW
rt = 4.166
P = V*V/R
=> P=24.03mW
Abi said:
1 decade ago
P=VI
BUT I=V/R
SO P=V.V/R
R=R1.R2/R1+R2
BCOZ RESISTORS ARE PARALLEL HERE.
R=4.166K ohms.
P=100/4.166K
=24mw.
BUT I=V/R
SO P=V.V/R
R=R1.R2/R1+R2
BCOZ RESISTORS ARE PARALLEL HERE.
R=4.166K ohms.
P=100/4.166K
=24mw.
Viju said:
1 decade ago
Rt=25*5/30.
=5/6 kohm.
P=V*V/R.
=100*6/5.
=24mW.
=5/6 kohm.
P=V*V/R.
=100*6/5.
=24mW.
Shahid said:
1 decade ago
@Jayashree.
Both the resistors are parallel to each other means (25*5) / (25+5) =4. 16.
Both the resistors are parallel to each other means (25*5) / (25+5) =4. 16.
ANITA NAGAR said:
1 decade ago
RT = R1*R2\(R1+R2) = 4.166.
P = V^2\R = 24.03MW.
P = V^2\R = 24.03MW.
Mani said:
7 years ago
We know p=v*v/R.
Given R1&R2 are connected in parallel,
R1 = 25k&R2=5k,
R = R1llR2,
R = R1*R2/R1+R2=4.16kohms,
P = 10*10/4.16*10^3,
P = 24mwatts.
Given R1&R2 are connected in parallel,
R1 = 25k&R2=5k,
R = R1llR2,
R = R1*R2/R1+R2=4.16kohms,
P = 10*10/4.16*10^3,
P = 24mwatts.
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