Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 21)
21.
When a parallel 5 k
resistor and a 25 k
resistor have a 10 V supply, what is the total power loss?


Discussion:
13 comments Page 2 of 2.
Deepika.S said:
6 years ago
P=v*v/R.
R= (R1*R2) / (R1+R2).
R= (5*25) / (5+25).
R=4.16*10^3ohms.
P= (10*10) / (4.16*10^3).
P=24*10^-3.
P=24mwatts.
R= (R1*R2) / (R1+R2).
R= (5*25) / (5+25).
R=4.16*10^3ohms.
P= (10*10) / (4.16*10^3).
P=24*10^-3.
P=24mwatts.
Santhanakumari said:
4 years ago
Please clear the solution in detail. @Deepika.
p= 24 * 10^-3.
And P = 24 mwatts.
p= 24 * 10^-3.
And P = 24 mwatts.
Santhanakumari said:
4 years ago
Please clear the solution in detail. @Deepika.
p= 24 * 10^-3.
And P = 24 mwatts.
p= 24 * 10^-3.
And P = 24 mwatts.
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