### Discussion :: Parallel Circuits - General Questions (Q.No.21)

Sangeetha said: (Jan 6, 2011) | |

RT=4.166k V=10 P=V2/RT P=24mW |

Jayasree said: (Feb 2, 2011) | |

How can RT be 4.166 k ? Since both resistors are parallel to each other RT=2.5 ohms na ? |

Mohammad Umair Kabir said: (Jul 26, 2011) | |

Since resistors are parallel so RT will be 1/RT = 1/R1 + 1/R2 1/RT = 1/5 + 1/25 = 6/25 RT = 25/6 or 4.16K I = V/R = 10/(25/6) = 2.4 mA So P = VI = (10)(2.4)= 24 mW |

Chinnu said: (Jan 27, 2012) | |

Since, r1||r2 rt = 4.166 P = V*V/R => P=24.03mW |

Abi said: (Jun 2, 2012) | |

P=VI BUT I=V/R SO P=V.V/R R=R1.R2/R1+R2 BCOZ RESISTORS ARE PARALLEL HERE. R=4.166K ohms. P=100/4.166K =24mw. |

Viju said: (Jun 29, 2012) | |

Rt=25*5/30. =5/6 kohm. P=V*V/R. =100*6/5. =24mW. |

Shahid said: (Sep 25, 2012) | |

@Jayashree. Both the resistors are parallel to each other means (25*5) / (25+5) =4. 16. |

Anita Nagar said: (Jul 5, 2013) | |

RT = R1*R2\(R1+R2) = 4.166. P = V^2\R = 24.03MW. |

Prashant said: (Jun 4, 2017) | |

R1 =5K THATS WHY P1 =10*2/5K =20mw (P=V2/R). R2= 25K THATS WHY P2 = 10*2/25K =4mw.(P=V2/R). SO, P = P1+P2 =24mw. |

Mani said: (May 1, 2018) | |

We know p=v*v/R. Given R1&R2 are connected in parallel, R1 = 25k&R2=5k, R = R1llR2, R = R1*R2/R1+R2=4.16kohms, P = 10*10/4.16*10^3, P = 24mwatts. |

Deepika.S said: (Dec 17, 2019) | |

P=v*v/R. R= (R1*R2) / (R1+R2). R= (5*25) / (5+25). R=4.16*10^3ohms. P= (10*10) / (4.16*10^3). P=24*10^-3. P=24mwatts. |

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