Discussion :: Parallel Circuits - General Questions (Q.No.21)
When a parallel 5 k resistor and a 25 k resistor have a 10 V supply, what is the total power loss?
Answer: Option C
No answer description available for this question.
|Sangeetha said: (Jan 6, 2011)|
|Jayasree said: (Feb 2, 2011)|
|How can RT be 4.166 k ?
Since both resistors are parallel to each other RT=2.5 ohms na ?
|Mohammad Umair Kabir said: (Jul 26, 2011)|
|Since resistors are parallel so RT will be
1/RT = 1/R1 + 1/R2
1/RT = 1/5 + 1/25 = 6/25
RT = 25/6 or 4.16K
I = V/R = 10/(25/6) = 2.4 mA
So P = VI = (10)(2.4)= 24 mW
|Chinnu said: (Jan 27, 2012)|
rt = 4.166
P = V*V/R
|Abi said: (Jun 2, 2012)|
BCOZ RESISTORS ARE PARALLEL HERE.
|Viju said: (Jun 29, 2012)|
|Shahid said: (Sep 25, 2012)|
Both the resistors are parallel to each other means (25*5) / (25+5) =4. 16.
|Anita Nagar said: (Jul 5, 2013)|
|RT = R1*R2\(R1+R2) = 4.166.
P = V^2\R = 24.03MW.
|Prashant said: (Jun 4, 2017)|
|R1 =5K THATS WHY P1 =10*2/5K =20mw (P=V2/R).
R2= 25K THATS WHY P2 = 10*2/25K =4mw.(P=V2/R).
P = P1+P2 =24mw.
|Mani said: (May 1, 2018)|
|We know p=v*v/R.
Given R1&R2 are connected in parallel,
R1 = 25k&R2=5k,
R = R1llR2,
R = R1*R2/R1+R2=4.16kohms,
P = 10*10/4.16*10^3,
P = 24mwatts.
Post your comments here:
Email : (optional)
» Your comments will be displayed only after manual approval.