Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 21)
21.
When a parallel 5 k
resistor and a 25 k
resistor have a 10 V supply, what is the total power loss?


Discussion:
13 comments Page 2 of 2.
Mohammad Umair Kabir said:
1 decade ago
Since resistors are parallel so RT will be
1/RT = 1/R1 + 1/R2
1/RT = 1/5 + 1/25 = 6/25
RT = 25/6 or 4.16K
I = V/R = 10/(25/6) = 2.4 mA
So P = VI = (10)(2.4)= 24 mW
1/RT = 1/R1 + 1/R2
1/RT = 1/5 + 1/25 = 6/25
RT = 25/6 or 4.16K
I = V/R = 10/(25/6) = 2.4 mA
So P = VI = (10)(2.4)= 24 mW
Jayasree said:
1 decade ago
How can RT be 4.166 k ?
Since both resistors are parallel to each other RT=2.5 ohms na ?
Since both resistors are parallel to each other RT=2.5 ohms na ?
Sangeetha said:
1 decade ago
RT=4.166k
V=10
P=V2/RT
P=24mW
V=10
P=V2/RT
P=24mW
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