Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 10)
10.
Which component is shorted?
Discussion:
49 comments Page 2 of 5.
Bhadmanathan.c said:
1 decade ago
As we all know, voltage is constant in parallel circuit. So I = V/R.
Current through R1 = 12mA.
Similarly through R2, R3 and R4 is 6mA, 4mA and 3mA.
Open circuit = No current or less current flows.
Short circuit = Large current flows.
Here R4 has Max current flow. So it would be short circuited.
Current through R1 = 12mA.
Similarly through R2, R3 and R4 is 6mA, 4mA and 3mA.
Open circuit = No current or less current flows.
Short circuit = Large current flows.
Here R4 has Max current flow. So it would be short circuited.
Rakhul said:
2 years ago
very well said @Pankaj.
As per the logic the galvanometer is saying 2.4 A is going next, so all three galvanometers are denoting 2.4A,
So, all three branches don't take current so, 2.4 A chooses path 4 I mean R4. And the low resistance path is available in R4 only right?
Correct me If I am wrong.
As per the logic the galvanometer is saying 2.4 A is going next, so all three galvanometers are denoting 2.4A,
So, all three branches don't take current so, 2.4 A chooses path 4 I mean R4. And the low resistance path is available in R4 only right?
Correct me If I am wrong.
Paullace said:
9 years ago
I think that is no so complex, in this case, it doesn't matter if the G is conductance or galvanometer.
If the short circuit wasn't in R4 , is so simple as the ammeter that is connected between R3 and R4 should display 0.0000A instead of 2.4A. So R4 should be shorted.
If the short circuit wasn't in R4 , is so simple as the ammeter that is connected between R3 and R4 should display 0.0000A instead of 2.4A. So R4 should be shorted.
Pankaj said:
1 decade ago
G is galvanometer and it measure current. 2.4 A is in the next G so no current through the R1. Similarly, no current through R2, R3 and finally whole current through R4. So R4 is short circuited and others are open circuit.
(2)
Akshay Prakash said:
1 decade ago
G stands for Galvanometer here i suppose, that's why 'A' is written by its side to show that it is being used an ammeter.
& since current is same in all branches therefore,r1,r2,r3 are open and only r4 is in circuit..
& since current is same in all branches therefore,r1,r2,r3 are open and only r4 is in circuit..
Shivanand said:
9 years ago
Very simple just observe that all galvanometers are reading the same current there id is no current which is flowing through the r1 r2 r3 and at last to form the loop so that current can flow r4 must be short circuited.
(1)
Sreeyush Sudhakaran said:
1 decade ago
1) 0=(I2-I1)X1K+(I2-I3)X2K
2) 0=(I3-I2)X2K+(I3-I4)X3K
3) 0=(I4-I3)X3K+I4X4K (R4=4k)
From given figure I1=I2=I3=I4=2.4A Substituing in 1,2,3
It satifies 1,2 it will be true and for 3 if R4 is shorted.
2) 0=(I3-I2)X2K+(I3-I4)X3K
3) 0=(I4-I3)X3K+I4X4K (R4=4k)
From given figure I1=I2=I3=I4=2.4A Substituing in 1,2,3
It satifies 1,2 it will be true and for 3 if R4 is shorted.
Ganapathi said:
1 decade ago
Current is always passes through the small resistance. Aaccording to the kvl the r4 having high resistance than r3+2400g.
So the final answer is the r4. and here g stands for conductance. i.e 1/R.
So the final answer is the r4. and here g stands for conductance. i.e 1/R.
Ravi said:
1 decade ago
Guys, they are asking which of these resistors is faulty (thus creating a shorted path) and they have shown us that no current flows through first three resistors, that means R4 is shorted.
Pravin said:
1 decade ago
Pankaj answer is the best explained. See the value all the galvanometer is same. It tells that current is not passing through R1, R2, R3. The entire current 2. 400A is passing through R4.
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