Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 11)
11.
What would these meter readings indicate about the circuit in the given circuit?
Meter Readings: I = 7.6 mA, V = 12 V
Discussion:
17 comments Page 2 of 2.
Samir said:
9 years ago
Thank you guys for giving a clear explanation.
Addy said:
9 years ago
Just look at the fig. above, there is showing batteries positive lead is connected to ground. Not a short to another component which is also grounded. If positive supply connect to the ground else is there current flow in the circuit! Please tell me.
Pratiksha said:
9 years ago
Well said, thanks for the given explanation.
Maan said:
8 years ago
I agree @Saichaitanya.
Mohan said:
1 decade ago
I agree with Saichaithanya.
Muhammad Feroz Aftab said:
7 years ago
Perfect Answer, thanks @Saichaitanya.
Himanshu Verma said:
1 decade ago
Case1 :When R1 is open,
then the effective resistance R = R2||R3
i.e. 5K||2K = 10/7 K
then current I = V/R = (12*7)/10K = 8.4 mA(Which is not correct ans i.e 7.6 mA)
Case2 : When R2 is open,
then the effective resistance R = R1||R3
i.e. 7.5K||2K = 30/19 K
then current I = V/R = (12*19)/30K = 7.6 mA(Which is d correct ans i.e 7.6 mA)
Case3: When the fuse is open,
then it is not possible to obtain voltage of 12 V
So the correct answer is option [b].
then the effective resistance R = R2||R3
i.e. 5K||2K = 10/7 K
then current I = V/R = (12*7)/10K = 8.4 mA(Which is not correct ans i.e 7.6 mA)
Case2 : When R2 is open,
then the effective resistance R = R1||R3
i.e. 7.5K||2K = 30/19 K
then current I = V/R = (12*19)/30K = 7.6 mA(Which is d correct ans i.e 7.6 mA)
Case3: When the fuse is open,
then it is not possible to obtain voltage of 12 V
So the correct answer is option [b].
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