Electronics - Bipolar Junction Transistors (BJT) - Discussion
Discussion Forum : Bipolar Junction Transistors (BJT) - General Questions (Q.No. 19)
19.
What is the current gain for a common-base configuration where IE = 4.2 mA and IC = 4.0 mA?
Discussion:
9 comments Page 1 of 1.
DANIEL.GNP said:
1 decade ago
It is common base configuration:
Circuit configuration of a bipolar transistor where emitter is the input electrode, collector is the output electrode and base is the reference electrode for both input and output. and it is gnd.
i.e.,
Current gain=I(out)/I(in) at RL=0.
4.0/4.2 = 0.95.
WHERE IC=O/P CURRENT AND IE =I/P CURRENT.
Circuit configuration of a bipolar transistor where emitter is the input electrode, collector is the output electrode and base is the reference electrode for both input and output. and it is gnd.
i.e.,
Current gain=I(out)/I(in) at RL=0.
4.0/4.2 = 0.95.
WHERE IC=O/P CURRENT AND IE =I/P CURRENT.
Dishant garg said:
1 decade ago
For common base configuration, current gain is alpha. Its value lies b/w 0.05-0.99. Ic=alpha*Ie.
(1)
Mahesh Metri said:
6 years ago
Given Data :
IE=4.2ma
IC=4.0mA.
Where, Alpha= IC/IE.
4.0/4.2=0.95.
IE=4.2ma
IC=4.0mA.
Where, Alpha= IC/IE.
4.0/4.2=0.95.
Devaki said:
1 decade ago
current gain = Ic / Ie
= 4 / 4.2
= 0.95
= 4 / 4.2
= 0.95
Vrushali wankhade said:
1 decade ago
Alpha always ranges from 0.95 to 0.98.
And alpha = ic/ie.
And alpha = ic/ie.
Nagesh patil said:
8 years ago
α=IC/IE.
there for α = 4.0/4.2 =0.95.
there for α = 4.0/4.2 =0.95.
Lov said:
1 decade ago
alpha=Ic/Ie
which is always less than 1.
which is always less than 1.
Varun Dhawan said:
1 decade ago
Alpha = Ic/Ie = 4.0/4.2 = 0.95.
Pradhan kantwa said:
5 years ago
Ic/Ie.
4.0ma/4.2ma = 0.95.
4.0ma/4.2ma = 0.95.
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