Electronics - Bipolar Junction Transistors (BJT) - Discussion
Discussion Forum : Bipolar Junction Transistors (BJT) - General Questions (Q.No. 19)
19.
What is the current gain for a common-base configuration where IE = 4.2 mA and IC = 4.0 mA?
Discussion:
9 comments Page 1 of 1.
Pradhan kantwa said:
5 years ago
Ic/Ie.
4.0ma/4.2ma = 0.95.
4.0ma/4.2ma = 0.95.
Mahesh Metri said:
6 years ago
Given Data :
IE=4.2ma
IC=4.0mA.
Where, Alpha= IC/IE.
4.0/4.2=0.95.
IE=4.2ma
IC=4.0mA.
Where, Alpha= IC/IE.
4.0/4.2=0.95.
Nagesh patil said:
8 years ago
α=IC/IE.
there for α = 4.0/4.2 =0.95.
there for α = 4.0/4.2 =0.95.
Dishant garg said:
1 decade ago
For common base configuration, current gain is alpha. Its value lies b/w 0.05-0.99. Ic=alpha*Ie.
(1)
Vrushali wankhade said:
1 decade ago
Alpha always ranges from 0.95 to 0.98.
And alpha = ic/ie.
And alpha = ic/ie.
Varun Dhawan said:
1 decade ago
Alpha = Ic/Ie = 4.0/4.2 = 0.95.
DANIEL.GNP said:
1 decade ago
It is common base configuration:
Circuit configuration of a bipolar transistor where emitter is the input electrode, collector is the output electrode and base is the reference electrode for both input and output. and it is gnd.
i.e.,
Current gain=I(out)/I(in) at RL=0.
4.0/4.2 = 0.95.
WHERE IC=O/P CURRENT AND IE =I/P CURRENT.
Circuit configuration of a bipolar transistor where emitter is the input electrode, collector is the output electrode and base is the reference electrode for both input and output. and it is gnd.
i.e.,
Current gain=I(out)/I(in) at RL=0.
4.0/4.2 = 0.95.
WHERE IC=O/P CURRENT AND IE =I/P CURRENT.
Devaki said:
1 decade ago
current gain = Ic / Ie
= 4 / 4.2
= 0.95
= 4 / 4.2
= 0.95
Lov said:
1 decade ago
alpha=Ic/Ie
which is always less than 1.
which is always less than 1.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers