Electronics - Analog and Digital Converters - Discussion

Discussion Forum : Analog and Digital Converters - General Questions (Q.No. 2)
2.
A 4-bit R/2R digital-to-analog (DAC) converter has a reference of 5 volts. What is the analog output for the input code 0101.
0.3125 V
3.125 V
0.78125 V
–3.125 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
34 comments Page 2 of 4.

Nitu said:   1 decade ago
Vo = (Rf/R)(Vref)(Do/16+D1/8+D2/4+D3/2).

Ajit patil said:   7 years ago
Thanks @Vidya.

Chandrashekhar pantina said:   6 years ago
5/16*(5) = 1.5625V.

As R/2R network so,
1.5625*2 = 3.125V.

Chandrashekhar pantina said:   6 years ago
5/16*5 = 1.5625.

As R/2R so 1.5635*2 = 5.125V.

Pradeep sharma said:   6 years ago
It should be 1.5 because it is resolution * decimal equivalent
And it is 4 bit dac so 2^n =16.

Vishnu said:   4 years ago
Given,
Data (msb)0101(lsb).
Now v0 = (5/2)(1(lsb)/2^0 + 0 + 1/2^2 + 0)
=5/2 * 5/4
= 25/8 = 3.125.

Panda said:   4 years ago
If the input code is 0101 then the answer should be 1.5625 volts. If we chose from the answer side then the input code should be 1010.

AL said:   3 years ago
In 4 bits, 1 bit is reserved to sign (pos or neg). So the resolution should be would be 5/2^3.

Vimal said:   1 decade ago
Here most significant bit '0' then it's value can be 5 (0/2+1/4+0/8+1/16).

Shah said:   1 decade ago
MOST EASY METHOD:

V(0ut) = (Vi/8)*digital input.


Post your comments here:

Your comments will be displayed after verification.