Electronics - Analog and Digital Converters - Discussion

Discussion Forum : Analog and Digital Converters - General Questions (Q.No. 2)
2.
A 4-bit R/2R digital-to-analog (DAC) converter has a reference of 5 volts. What is the analog output for the input code 0101.
0.3125 V
3.125 V
0.78125 V
–3.125 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
35 comments Page 2 of 4.

Subodhunu said:   9 years ago
Va= Vref(1/2 + 0/4 + 1/8 + 0/16) (because 0101).
= 3.125 v.

Mohith said:   8 years ago
Vref/8=5/8=0.625,
Va/0.625=5=0101,
Va=3.125.

Ajit patil said:   7 years ago
Thanks @Vidya.

Chandrashekhar pantina said:   7 years ago
5/16*(5) = 1.5625V.

As R/2R network so,
1.5625*2 = 3.125V.

Chandrashekhar pantina said:   7 years ago
5/16*5 = 1.5625.

As R/2R so 1.5635*2 = 5.125V.

Vishnu said:   5 years ago
Given,
Data (msb)0101(lsb).
Now v0 = (5/2)(1(lsb)/2^0 + 0 + 1/2^2 + 0)
=5/2 * 5/4
= 25/8 = 3.125.

AL said:   4 years ago
In 4 bits, 1 bit is reserved to sign (pos or neg). So the resolution should be would be 5/2^3.

Cheng said:   2 months ago
My answer is option C.

Explanation: The main advantage of these converters is that is possible to transmit frequency even in a noisy environment or in an isolated form.

The dual slope is preferred over charge balancing ADC.

Pushpinder kansal said:   1 decade ago
v=5(5/16)
=1.5625
now 1.5625*2=3.125ans

Askani said:   2 decades ago
Formula= Vref/2^n(msb bit*2^0+nextbit*2^1+nextbit*2^2+lsb bit*2^3)


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