Electronics - Analog and Digital Converters - Discussion
Discussion Forum : Analog and Digital Converters - General Questions (Q.No. 2)
2.
A 4-bit R/2R digital-to-analog (DAC) converter has a reference of 5 volts. What is the analog output for the input code 0101.
Discussion:
34 comments Page 2 of 4.
KIRAN said:
9 years ago
Analog output for the input code 0101.
Formula: Va = Vref / 2^n * input code bit (Start from MSB).
Given : Vref = 5V; Input code bit = 0101.
Va = (Vref / 2^0 * 0) + (Vref / 2^1) * 1) + (Vref / 2^2 * 0) + (Vref / 2^3 * 1).
Va = (5 / 1 * 0) + (5 / 2 * 1) + (5 / 2^2 * 0) + (5 / 2^3 * 1).
Va = (5 / 1 * 0) + (5 / 2 * 1) + (5 / 4 * 0) + (5 / 8 * 1).
Va = (0) + (2.5) + (0) + (0.625).
Va = 3.125 V.
Formula: Va = Vref / 2^n * input code bit (Start from MSB).
Given : Vref = 5V; Input code bit = 0101.
Va = (Vref / 2^0 * 0) + (Vref / 2^1) * 1) + (Vref / 2^2 * 0) + (Vref / 2^3 * 1).
Va = (5 / 1 * 0) + (5 / 2 * 1) + (5 / 2^2 * 0) + (5 / 2^3 * 1).
Va = (5 / 1 * 0) + (5 / 2 * 1) + (5 / 4 * 0) + (5 / 8 * 1).
Va = (0) + (2.5) + (0) + (0.625).
Va = 3.125 V.
Subodhunu said:
8 years ago
Va= Vref(1/2 + 0/4 + 1/8 + 0/16) (because 0101).
= 3.125 v.
= 3.125 v.
Nitu said:
1 decade ago
Vo = (Rf/R)(Vref)(Do/16+D1/8+D2/4+D3/2).
Ajit patil said:
7 years ago
Thanks @Vidya.
Chandrashekhar pantina said:
7 years ago
5/16*(5) = 1.5625V.
As R/2R network so,
1.5625*2 = 3.125V.
As R/2R network so,
1.5625*2 = 3.125V.
Chandrashekhar pantina said:
7 years ago
5/16*5 = 1.5625.
As R/2R so 1.5635*2 = 5.125V.
As R/2R so 1.5635*2 = 5.125V.
Vishnu said:
5 years ago
Given,
Data (msb)0101(lsb).
Now v0 = (5/2)(1(lsb)/2^0 + 0 + 1/2^2 + 0)
=5/2 * 5/4
= 25/8 = 3.125.
Data (msb)0101(lsb).
Now v0 = (5/2)(1(lsb)/2^0 + 0 + 1/2^2 + 0)
=5/2 * 5/4
= 25/8 = 3.125.
AL said:
4 years ago
In 4 bits, 1 bit is reserved to sign (pos or neg). So the resolution should be would be 5/2^3.
Vimal said:
2 decades ago
Here most significant bit '0' then it's value can be 5 (0/2+1/4+0/8+1/16).
Shah said:
1 decade ago
MOST EASY METHOD:
V(0ut) = (Vi/8)*digital input.
V(0ut) = (Vi/8)*digital input.
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