Electronics - Analog and Digital Converters - Discussion
Discussion Forum : Analog and Digital Converters - General Questions (Q.No. 2)
2.
A 4-bit R/2R digital-to-analog (DAC) converter has a reference of 5 volts. What is the analog output for the input code 0101.
Discussion:
34 comments Page 1 of 4.
AL said:
3 years ago
In 4 bits, 1 bit is reserved to sign (pos or neg). So the resolution should be would be 5/2^3.
Panda said:
4 years ago
If the input code is 0101 then the answer should be 1.5625 volts. If we chose from the answer side then the input code should be 1010.
Vishnu said:
4 years ago
Given,
Data (msb)0101(lsb).
Now v0 = (5/2)(1(lsb)/2^0 + 0 + 1/2^2 + 0)
=5/2 * 5/4
= 25/8 = 3.125.
Data (msb)0101(lsb).
Now v0 = (5/2)(1(lsb)/2^0 + 0 + 1/2^2 + 0)
=5/2 * 5/4
= 25/8 = 3.125.
Pradeep sharma said:
6 years ago
It should be 1.5 because it is resolution * decimal equivalent
And it is 4 bit dac so 2^n =16.
And it is 4 bit dac so 2^n =16.
Chandrashekhar pantina said:
6 years ago
5/16*(5) = 1.5625V.
As R/2R network so,
1.5625*2 = 3.125V.
As R/2R network so,
1.5625*2 = 3.125V.
Chandrashekhar pantina said:
6 years ago
5/16*5 = 1.5625.
As R/2R so 1.5635*2 = 5.125V.
As R/2R so 1.5635*2 = 5.125V.
Ajit patil said:
7 years ago
Thanks @Vidya.
Ravi said:
7 years ago
Thanks @Vidya.
(1)
Mohith said:
8 years ago
Vref/8=5/8=0.625,
Va/0.625=5=0101,
Va=3.125.
Va/0.625=5=0101,
Va=3.125.
Subodhunu said:
8 years ago
Va= Vref(1/2 + 0/4 + 1/8 + 0/16) (because 0101).
= 3.125 v.
= 3.125 v.
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