Electronics - Analog and Digital Converters - Discussion
Discussion Forum : Analog and Digital Converters - General Questions (Q.No. 2)
2.
A 4-bit R/2R digital-to-analog (DAC) converter has a reference of 5 volts. What is the analog output for the input code 0101.
Discussion:
34 comments Page 1 of 4.
Vimal said:
1 decade ago
Here most significant bit '0' then it's value can be 5 (0/2+1/4+0/8+1/16).
Askani said:
1 decade ago
Formula= Vref/2^n(msb bit*2^0+nextbit*2^1+nextbit*2^2+lsb bit*2^3)
Nirja said:
1 decade ago
Vo = 5(Vi/16)
= 5(5/16)
= 1.5625
= 5(5/16)
= 1.5625
Sundar said:
1 decade ago
A 4-bit R/2R digital-to-analog....
Here what about R/2R...?
I think 1.5625 x 2 = 3.125V
Here what about R/2R...?
I think 1.5625 x 2 = 3.125V
Anuradha awasthi said:
1 decade ago
Formula= Vref/2^n(msb bit*2^0+nextbit*2^1+nextbit*2^2+lsb bit*2^3)
where, n= no. of bits
output= (5/2^4)(0*1+1*2+0*4+1*8)
= (5/16)(10)
= 3.125 V
where, n= no. of bits
output= (5/2^4)(0*1+1*2+0*4+1*8)
= (5/16)(10)
= 3.125 V
Nilima sinha said:
1 decade ago
Vo=Vref(0*2^0+1*2^-1+0*2^-2+1*2^-3)
=5(0.5+.25)
=3.125V
=5(0.5+.25)
=3.125V
Thanihai said:
1 decade ago
Formula= Vref/2^n(msb bit*2^3+nextbit*2^2+nextbit*2^1+lsb bit*2^0)
where, n= no. of bits
output= (5/2^4)(0*8+1*4+0*2+1*1)
= (5/16)(5)
= 1.5625 V
This should be the correct answer for any type of DACs.
where, n= no. of bits
output= (5/2^4)(0*8+1*4+0*2+1*1)
= (5/16)(5)
= 1.5625 V
This should be the correct answer for any type of DACs.
Kiran said:
1 decade ago
It can b solved as =ref. voltage * binary equivalent/ total no of steps.
Ankur said:
1 decade ago
Formula= Vref/{(2^n)-1}(msb bit*2^0+nextbit*2^1+nextbit*2^2+lsb bit*2^3)
where, n= no. of bits
output= (5/2^4)(0*1+1*2+0*4+1*8)
= (5/15)(10)
= 3.125 V
where, n= no. of bits
output= (5/2^4)(0*1+1*2+0*4+1*8)
= (5/15)(10)
= 3.125 V
Pushpinder kansal said:
1 decade ago
v=5(5/16)
=1.5625
now 1.5625*2=3.125ans
=1.5625
now 1.5625*2=3.125ans
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