Electronics - Analog and Digital Converters - Discussion
Discussion Forum : Analog and Digital Converters - General Questions (Q.No. 2)
2.
A 4-bit R/2R digital-to-analog (DAC) converter has a reference of 5 volts. What is the analog output for the input code 0101.
Discussion:
35 comments Page 4 of 4.
Ashu said:
1 decade ago
Vo = 5(0/16+1/8+0/4+1/2).
Vo = 3.125.
Vo = 3.125.
Vaishnavi murugan said:
1 decade ago
Formula = [Vref/(2^n)] {msb bit * 2^0 + next bit * 2^1 + next bit * 2^2 + lsb bit * 2^3}.
Where n = no of bit,
Solution:
Vref = 5v;
n = 4;
=> (5/(2^4)) {0*0 + 1*2 + 0*4 + 1*8}
=> (5/16) {0 + 2 + 0 + 8}
=> (0.3125) {10}
=> 3.125.
Answer => 3.125.
Where n = no of bit,
Solution:
Vref = 5v;
n = 4;
=> (5/(2^4)) {0*0 + 1*2 + 0*4 + 1*8}
=> (5/16) {0 + 2 + 0 + 8}
=> (0.3125) {10}
=> 3.125.
Answer => 3.125.
GOPAL said:
1 decade ago
@Nirja.
Formula = (Vref/2^N)(dec equivalent of i/p).
N- is number of significant bits (here 3 as msb is 0).
Here 0101 = 101 hence consider 3 bit.
Therefore,
Vo = 5(Vi/8) = 3.12.
Formula = (Vref/2^N)(dec equivalent of i/p).
N- is number of significant bits (here 3 as msb is 0).
Here 0101 = 101 hence consider 3 bit.
Therefore,
Vo = 5(Vi/8) = 3.12.
Shah said:
1 decade ago
MOST EASY METHOD:
V(0ut) = (Vi/8)*digital input.
V(0ut) = (Vi/8)*digital input.
Vimal said:
2 decades ago
Here most significant bit '0' then it's value can be 5 (0/2+1/4+0/8+1/16).
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