# Electronics and Communication Engineering - Signals and Systems - Discussion

Discussion Forum : Signals and Systems - Section 1 (Q.No. 1)

1.

What about the stability of system in

Answer: Option

Explanation:

ROC include the unit circle hence it is stable.

Discussion:

49 comments Page 1 of 5.
Abdul Wahab said:
2 months ago

The System is unstable,

Since, the pole at z = 0.4 lies inside the unit circle and the other pole at z = 2 lies outside the unit circle.

For a system to be stable, all the poles must be inside the unit circle in the z-plane.

Therefore, the system is unstable.

Since, the pole at z = 0.4 lies inside the unit circle and the other pole at z = 2 lies outside the unit circle.

For a system to be stable, all the poles must be inside the unit circle in the z-plane.

Therefore, the system is unstable.

(4)

Usama said:
3 years ago

H(z) is actually z transform. Now finding the ROC:

The roots are 0.2, 2.

which makes a circle that encloses the unit circle, so the system is stable.

The roots are 0.2, 2.

which makes a circle that encloses the unit circle, so the system is stable.

(2)

Tushar said:
4 years ago

According to me, it is Unstable.

(1)

Chethan said:
7 years ago

No, it is unstable.

Nisha said:
7 years ago

The system is unstable. ROC doesn't include unit circle.

Rutuja said:
7 years ago

No, the system is unstable.

Vijay said:
7 years ago

Mix causal and anti-causal signal than it is stable.

Saritha said:
7 years ago

Poles are the right side of the circle. So it is stable.

Zahoor said:
7 years ago

Since one pole magnitude lies outside the unit circle so system is unstable.

Sridevi said:
7 years ago

Please give the explanation of the answer clearly.

Post your comments here:

Quick links

Quantitative Aptitude

Verbal (English)

Reasoning

Programming

Interview

Placement Papers