Electronics and Communication Engineering - Signals and Systems - Discussion
Discussion Forum : Signals and Systems - Section 1 (Q.No. 1)
1.
What about the stability of system in 
Answer: Option
Explanation:
ROC include the unit circle hence it is stable.
Discussion:
49 comments Page 1 of 5.
Abdul Wahab said:
10 months ago
The System is unstable,
Since, the pole at z = 0.4 lies inside the unit circle and the other pole at z = 2 lies outside the unit circle.
For a system to be stable, all the poles must be inside the unit circle in the z-plane.
Therefore, the system is unstable.
Since, the pole at z = 0.4 lies inside the unit circle and the other pole at z = 2 lies outside the unit circle.
For a system to be stable, all the poles must be inside the unit circle in the z-plane.
Therefore, the system is unstable.
(6)
Usama said:
3 years ago
H(z) is actually z transform. Now finding the ROC:
The roots are 0.2, 2.
which makes a circle that encloses the unit circle, so the system is stable.
The roots are 0.2, 2.
which makes a circle that encloses the unit circle, so the system is stable.
(2)
Tushar said:
5 years ago
According to me, it is Unstable.
(1)
Chethan said:
8 years ago
No, it is unstable.
Nisha said:
8 years ago
The system is unstable. ROC doesn't include unit circle.
Rutuja said:
8 years ago
No, the system is unstable.
Vijay said:
8 years ago
Mix causal and anti-causal signal than it is stable.
Saritha said:
8 years ago
Poles are the right side of the circle. So it is stable.
Zahoor said:
8 years ago
Since one pole magnitude lies outside the unit circle so system is unstable.
Sridevi said:
8 years ago
Please give the explanation of the answer clearly.
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