Electronics and Communication Engineering - Signals and Systems - Discussion

Discussion Forum : Signals and Systems - Section 1 (Q.No. 1)
1.
What about the stability of system in
system is stable
unstable
stable at 0.4
cant say
Answer: Option
Explanation:

ROC include the unit circle hence it is stable.

Discussion:
50 comments Page 2 of 5.

It's me . . . said:   8 years ago
System is stable.

For the system to be stable, the unit circle should lie between ROC.

Hence unit circle lie between 0.4 and 2.

Dhivya said:   8 years ago
Can anyone please explain how to solve these type of problem?

Iram said:   8 years ago
H(z) = (-3/4z)/(z-0.4) + (16/5z)/(z-2) this is final transfer function. by sketching its ROC it can be seen that pole at 2 Roc lie outside unity circle while pole at 0.4 Roc includes unity circle by expanding in an outward direction.

So, the system is stable.

RAM said:   8 years ago
Can't understand please can anyone explain it?

D.SIVASAMY said:   8 years ago
System is unstable because pole 2 locating outside the unit circle.

Meena said:   8 years ago
I don't understand. Please explain in detail.

Chethan said:   9 years ago
No, it is unstable.

Ramasubramanian said:   7 years ago
The system is unstable since the pole z=2 lies outside the UNIT circle.

Aiyoob said:   6 years ago
All poles are in the left half of s plane.

So, Use the concept of control system.

Meena chintha said:   6 years ago
Pole is Z=2, the unit circle is 1. So it is unstable.

Then how, it should be stable? Explain it.


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