Electronics and Communication Engineering - Signals and Systems - Discussion
Discussion Forum : Signals and Systems - Section 1 (Q.No. 1)
1.
What about the stability of system in 

Answer: Option
Explanation:
ROC include the unit circle hence it is stable.
Discussion:
50 comments Page 5 of 5.
Aman said:
1 decade ago
For stability we check mod of z which IC greater than 2 and 0.4. Hence we use upper limit that is z=2 which is outside uni circle, so system unstable.
Abhishek sharma said:
1 decade ago
Either question is incomplete or its a wrong answer. Please refer some standards texts before putting it up.
Bhuwan joshi said:
1 decade ago
Either they should give ROC.
4<z<2 for stability otherwise system will be unstable.
4<z<2 for stability otherwise system will be unstable.
LD Nagar said:
1 decade ago
The ROC is not given. So we can not say this signal is RHS or LHS. So this system is unstable.
Vikas said:
10 years ago
The condition of stable system is that the pole of a transfer function must be lie in the left half of s plane. So the system is unstable.
Hareesh said:
9 years ago
Here, we need to specify the region of convergence (ROC) (ROC:0. 4, <Z<2), then only it's possible to say, it is stable or not.
Other wise its difficult.
Other wise its difficult.
RAGHUVAMSI said:
9 years ago
Please explain the method to solve this question.
Devyanee chandra said:
9 years ago
I think the question is incomplete .
Without ROC, it is difficult to define or at least the signal type i.e. causal/non-causal /anti-causal should have been mentioned.
Without ROC, it is difficult to define or at least the signal type i.e. causal/non-causal /anti-causal should have been mentioned.
RAVI said:
9 years ago
The system is not stable.
Nisha said:
9 years ago
The system is unstable. ROC doesn't include unit circle.
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