Electronics and Communication Engineering - Signals and Systems - Discussion
Discussion Forum : Signals and Systems - Section 1 (Q.No. 1)
1.
What about the stability of system in 
Answer: Option
Explanation:
ROC include the unit circle hence it is stable.
Discussion:
50 comments Page 4 of 5.
Shivanand jaiswal said:
1 decade ago
roc of given problem z>2 and z>0.4 so intersection of this will be z>2 that is outside the unit circle tending to infinite this is an casual system but not stable.
Manan said:
1 decade ago
According to me system is unstable.
Shamsheer said:
1 decade ago
ROC is |Z|>2 and .4<|Z|<4/3.
Why everyone are concerned with pole Z=2?
Why everyone are concerned with pole Z=2?
Arun Kumar Gupta said:
1 decade ago
Without ROC one can't say that system is stable or not.
Mahesh said:
1 decade ago
Solve it can't understand.
Khalique said:
1 decade ago
How one can know the stability when ROC is unknown? In above question ROC can be inward, outward or. 4<|z|<2.
Rams said:
1 decade ago
It depends on ROC we can't say anything about stability.
Soumya said:
1 decade ago
Since the pole z=2 is outside the unit circle so it is unstable. II think the answer is wrong it cannot be stable.
Iman said:
1 decade ago
I think the ROC would have to be mentioned in the question to answer the question. Like 0.4 < |z| < 2.
Swapna said:
1 decade ago
I can't understand please explain that clearly.
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