Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion

Discussion Forum : Networks Analysis and Synthesis - Section 1 (Q.No. 20)
20.
In the circuit of figure, the switch is closed at t = 0. At t = 0+ the current through C is
4 A
2.5 A
3.1 A
0
Answer: Option
Explanation:

Capacitor behaves as a short-circuit at t = 0.

Discussion:
7 comments Page 1 of 1.

Subadra said:   5 years ago
As the capacitor is short the 3 ohm resistor will be parallel to short which will be short again. Hence the resistance of 5 should be considered.

Parth said:   6 years ago
At t=0+ capacitor is s.c.

Since current flow from 5-ohm resistor and voltage given is 20 v.
So I = V/R.
I = 20/5 = 4.

Vindhya said:   7 years ago
The capacitor acts as open ckt at t=0+, since c is shorted at t=0 then current is 0.

Nids said:   7 years ago
But for a DC voltage supply, the capacitor will act as an open circuit.

Then the current through the capacitor will be 0.

Yash said:   9 years ago
At the time t+, the capacitor is nearly short and the current find low resistance path so current through 3ohm is 0 that's why whole current flow capacitor.

Ashwini ojha said:   1 decade ago
Nope due to short in capacitor at t=0+ voltage drop across resistance of 3 ohm is zero so effective resistance is 5 ohm and answer is 4 A.

Sandeep said:   1 decade ago
If capacitor behave as short circuit than total resistance in circuit becomes equal to 8.

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