Electronics and Communication Engineering - Networks Analysis and Synthesis

6.
Power is drawn from a source at power factor 0.7. Pav = 300 watt. The reactive power is
0
105
100 VA
107 VA
Answer: Option
Explanation:

cos θ = 0.7 sin θ = 0.71

Pr = VI sin θ = x 300 x 0.7 107 VA.


7.
Two capacitors each of capacitance C and breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination is
0.5 C and 2 V
0.5 C and 0.5 V
C and V
2 C and 2 V
Answer: Option
Explanation:

Since the capacitors are in series, the total capacitance becomes 50%. Voltage across each is V.


8.
The current wave shown in figure is applied at t = 0 to a 0.1 F capacitor. At t = 1 s, the voltage across capacitor is
0 V
10 V
20 V
40 V
Answer: Option
Explanation:

Q = 4 x 0.5 = 2C and


9.
A capacitor can be represented by a capacitance C in parallel with a resistance R. For a good capacitor, the resistance R should be
very high
high
very low
low
Answer: Option
Explanation:

Very high R will mean low dielectric loss.


10.
If a sheet of a mica is inserted between the plates of an air capacitor, the capacitance
will increase
will return the same
will decrease
may increase or decrease
Answer: Option
Explanation:

For mica ∈r is more than that of air.