Electronics and Communication Engineering - Networks Analysis and Synthesis
Exercise : Networks Analysis and Synthesis - Section 4
- Networks Analysis and Synthesis - Section 14
- Networks Analysis and Synthesis - Section 27
- Networks Analysis and Synthesis - Section 26
- Networks Analysis and Synthesis - Section 25
- Networks Analysis and Synthesis - Section 24
- Networks Analysis and Synthesis - Section 23
- Networks Analysis and Synthesis - Section 22
- Networks Analysis and Synthesis - Section 21
- Networks Analysis and Synthesis - Section 20
- Networks Analysis and Synthesis - Section 19
- Networks Analysis and Synthesis - Section 18
- Networks Analysis and Synthesis - Section 17
- Networks Analysis and Synthesis - Section 16
- Networks Analysis and Synthesis - Section 15
- Networks Analysis and Synthesis - Section 1
- Networks Analysis and Synthesis - Section 13
- Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 11
- Networks Analysis and Synthesis - Section 10
- Networks Analysis and Synthesis - Section 9
- Networks Analysis and Synthesis - Section 8
- Networks Analysis and Synthesis - Section 7
- Networks Analysis and Synthesis - Section 6
- Networks Analysis and Synthesis - Section 5
- Networks Analysis and Synthesis - Section 4
- Networks Analysis and Synthesis - Section 3
- Networks Analysis and Synthesis - Section 2
6.
In the circuit shown in the figure, the current supplied by the sinusoidal current source I is
Answer: Option
Explanation:
I = (12)2 + (16)2 = 20 A.
7.
The frame of an electric motor is earthed through three earthing plates resistances 30 Ω, 20 Ω and 10 Ω respectively. During fault the energy dissipated by three plates are W1, W2 and W3. Then
Answer: Option
Explanation:
Energy dissipated by the plate with lowest resistance is maximum.
8.
If figure, power dissipated in 30Ω resistance will be maximum when value of R =
Answer: Option
Explanation:
When R = 0, circuit current = 
and power dissipated = 
watts, which is the maximum possible value.
9.
In the following non-planar graph no.of independent loop equations are
Answer: Option
Explanation:
L = B - N + 1 = 12 - 8 + 1 = 5.
10.
Two voltages are 50 ∠0 V and 75 ∠ - 60° V. The sum of these voltages is
Answer: Option
Explanation:
50Ð0 = 50 + j 0.75∠-60° = 37.5 - j 64.95
Sum = (50 + 37.5) - j 64.95 = 87.5 - j 64.95 = 109∠-36.6°
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