Electronics and Communication Engineering - Exam Questions Papers - Discussion

Discussion Forum : Exam Questions Papers - Exam Paper 12 (Q.No. 50)
50.
Consider two random processes x(t) and y(t) have zero mean, and they are individually stationary. The random process is z(t) = x(t) + y(t). Now when stationary processes are uncorrelated then power spectral density of z(t) is given by
Sx(f) + Sy(f) + 2Sxy(f)
Sx(f) + Sy(f) + 2Sxy(f) + 2Syx(f)
Sx(f) + Sy(f)
Sx(f) + Sy(f) - 2Sxy(f) - 2Syx(f)
Answer: Option
Explanation:

The autocorrelation function of z(t) is given by

Rz(t, u) = E[Z(t)Z(u)]

= E[(x(t) + y(t)) (x(u) + y(u))]

= E[x(t) x (u)] + E[x(t) y(u)] + E[y(t) x(u)] + E[y(t) y(u)]

= Rx(E, u) + Rxy(t, u) + Ryx(t, u) + Ry(t, u)

Defining t = t - u, we may therefore write Rz(t) = Rx(t) + Rxy(t) + Ryx(t) + Ry(t).

When the random process x(t) and y(t) are also jointly stationary.

Accordingly, taking the fourier transform of both sides of equation we get

Sz(f = Sx(f) + Sxy(f) + Syx(f) + Sy(f)

We thus see that the cross spectral densities Sxy(f) and Syx(f) represent the spectral components that must be added to the individual power spectral densities of a pair of correlated random processes in order to obtain the power spectral density of their sum.

When the stationary process x(t) and y(t) are uncorrelated the cross-sectional densities Sxy(f) and Syz(f) are zero

Sz(f) = Sx(f) + Sy(f).

Discussion:
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