Electronics and Communication Engineering - Exam Questions Papers - Discussion
Discussion Forum : Exam Questions Papers - Exam Paper 2 (Q.No. 15)
15.
The value of the integral 
is
is
Answer: Option
Explanation:
Compare this with
where s = 3.
Discussion:
3 comments Page 1 of 1.
Praveen said:
8 years ago
Laplace transform of sint = 1/(s^2+1) and laplace transform of e^(-3t)sint = 1/((s+3)^2+1).
now, t.e^(-3t)sint = d/dt(1/((s+3)^2+1).) = 2(s+3)/((s+3)^2+1))--------> 1.
at s = 0, we get 3/50 as answer from the above equation -----> 1.
now, t.e^(-3t)sint = d/dt(1/((s+3)^2+1).) = 2(s+3)/((s+3)^2+1))--------> 1.
at s = 0, we get 3/50 as answer from the above equation -----> 1.
Mayur said:
10 years ago
Will some one tell how?
Shiv said:
6 years ago
At s=0 how we get 3/20.
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