Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 11 (Q.No. 17)
17.
A sample of N type semiconductor has electron density of 6.25 x 108/cm2 at 300 K. If the intrinsic concentration of carriers in this sample is 2.5 x 1013/cm3 at this temperature, the hole density works out to be
Discussion:
3 comments Page 1 of 1.
Rommel said:
8 years ago
Ni^2 = Np*Ne.
Np = (2.5x10^13)^2/6.25x10^8 = 10^18.
Np = (2.5x10^13)^2/6.25x10^8 = 10^18.
Mukund said:
9 years ago
The electron density should be 6.25X10^18.
Mukund said:
9 years ago
Can anyone explain how?
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