Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 1 (Q.No. 47)
47.
Which of the following is true as regards photo emission?
Answer: Option
Explanation:
As wavelength decreases, frequency increases and maximum velocity of electron increases.
Discussion:
6 comments Page 1 of 1.
Simran said:
6 years ago
Here, E=hf= mv^2/2.
Nav said:
7 years ago
λ = c/f.
F=c/λ c is velocity f light so if lambda decreases then 'f' increases it results to velocity increase.
F=c/λ c is velocity f light so if lambda decreases then 'f' increases it results to velocity increase.
Lovi said:
8 years ago
I think Lambda is inversely proportional to frequency.
MANAV said:
8 years ago
Lambda is directly proportional to velocity.
Manav said:
8 years ago
Lambda = velocity/frequency which means lambda is directly proportional to frequency. Then how do velocity increases when wavelength decreases?
Vini said:
9 years ago
V=Lambada*Frequency.
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