Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 1 (Q.No. 16)
16.
An LED has a rating of 2 V and 10 mA. It is used along with 6V battery. The range of series resistance is
Answer: Option
Explanation:
R = 
= 400Ω.
R must be at least 400Ω so that current in LED does not exceed 10 mA.
Discussion:
3 comments Page 1 of 1.
Masoom said:
9 years ago
Please explanation the answer.
V.SARANYA said:
8 years ago
R=(V2-V1)/I.
= (6-2)/(10*10^-3),
= 4/(10^-2),
= 400ohm.
= (6-2)/(10*10^-3),
= 4/(10^-2),
= 400ohm.
(1)
NALLENDRAN said:
7 years ago
Thank you @Saranya.
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