Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 4 (Q.No. 19)
19.
In a bipolar junction transistor adc = 0.98, ICO= 2 μA and 1B = 15 μA. The collector current IC is
Answer: Option
Explanation:
Discussion:
5 comments Page 1 of 1.
GlennSid said:
3 years ago
Hence Ic =Ib*β
Saurabh kumar said:
5 years ago
Ic = b * ib+(1+b)ico.
ic = 49 * 15 + 50 * 2,
Ic = 0.835ma.
ic = 49 * 15 + 50 * 2,
Ic = 0.835ma.
(1)
Weeknd2020 said:
5 years ago
Ic = Beta (Ib) + Ico.
Sandy said:
8 years ago
The correct answer is C in micro amp.
Amit kumar said:
10 years ago
Ic = B*Ib+(1+B)*Ico.
If y apply this formula why will get 835 mA.
So correct answer is 'C'.
If y apply this formula why will get 835 mA.
So correct answer is 'C'.
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