Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion

Discussion Forum : Electronic Devices and Circuits - Section 15 (Q.No. 1)
1.
The product kT (where k is Boltzmann's constant and T is absolute temperature) at room temperature is about
0.051 eV
0.026 eV
0.01 eV
0.001 eV
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
7 comments Page 1 of 1.

Akitete said:   8 years ago
(1.38x10^-23)(25)/1.602x10^-19.

= 0.26.

Shadan said:   8 years ago
@Akitete.

How 25 came?

Gab said:   8 years ago
@Shadan.

It is the standard room temp for electronics.

Daniel said:   8 years ago
@Akitete.

What is 1.602x10^-19?

Jason said:   6 years ago
k = 1.38x10^-23 electron charge = 1.6x10^-19.
(1.38x10^-23)(273)/(1.6x10^-19) = 0.02.

GLENNFREY SID said:   6 years ago
KT/q= 1.38x10^23 (273+25) /1.61x10^-19 =0.0256 eV.

Nikunj said:   10 months ago
The product kT at room temperature is about 0.0256 eV.

Here's how we can arrive at this value:

* Room temperature: Room temperature is typically considered to be around 25 degrees Celsius, which is equivalent to 298 Kelvin (K).

* Boltzmann constant: The Boltzmann constant (k) is a fundamental physical constant relating the average kinetic energy of particles in a gas with the temperature of the gas. Its value is approximately 1.38 x 10^-23 joules per kelvin (J/K).

* Calculation: To find kT at room temperature, we simply multiply the Boltzmann constant by the temperature in Kelvin:
kT = (1.38 x 10^-23 J/K) * (298 K) = 4.11 x 10^-21 J.

* Conversion to electronvolts: It's often convenient to express energy in electronvolts (eV), which is the amount of energy gained by an electron when it moves through a potential difference of one volt. To convert joules to electronvolts, we divide by the elementary charge (e), which is approximately 1.60 x 10^-19 coulombs (C):
kT (eV) = (4.11 x 10^-21 J) / (1.60 x 10^-19 C) = 0.0256 eV.

Therefore, the product kT at room temperature is approximately 0.0256 eV.

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