Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion

Discussion Forum : Electronic Devices and Circuits - Section 8 (Q.No. 1)

Assertion (A): Hall effect is used to find the type of semiconductor.

Reason (R): When a specimen of semiconductor carrying current I lies in a magnetic field the force on electrons and holes is in opposite directions.

Both A and R are true and R is correct explanation of A
Both A and R are true but R is not a correct explanation of A
A is true but R is false
A is false but R is true
Answer: Option
No answer description is available. Let's discuss.
1 comments Page 1 of 1.

Joshnavi said:   4 years ago
When a current. Carrying semiconductor is placed in a magnetic field charge inside the semiconductor experience a force which is perpendicular to both magnetic field and current.

Lorenz force( f) = q *( v * B) ----> (1)
In a semiconductor electric field is also present due to electrons so electric force.
F(e)= q E ----> (2)

Solving ...
V*B = E ----> (3)
Since E= v/t
V*B=v/t ----> (4)
Since, J = q * n * v
V = J/q*n .. Substitute in eq 4.
VB = (J/qnt)
Since, J = current (i)/ Area of semiconductor(A)

A= thickness of semiconductor * width of the semiconductor
A= w * t
J = I / w t
( I * B )/(w q n) = V. Hall voltage
Hall coefficient R=(1/ qn )
R = v * w / (B * I )
R is inversely proportional to I and B.

For n-type semiconductor, electrons accommodate at bottom of a semiconductor due to opposite force.

For p-type semiconductor, electrons accommodate at top of the semiconductor.

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