Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 4 (Q.No. 20)
20.
The voltage across the secondary of the transformer in a half wave rectifier with a shunt capacitor filter is 50 volts. The maximum voltage that will occur on the reverse biased diode will be
Discussion:
7 comments Page 1 of 1.
Aswathy said:
4 years ago
Yes, you are right @Arunvijay.
(1)
Zulu Chungtia said:
6 years ago
Yes, you are right @Arunvijay.
Arunvijay said:
7 years ago
Due to capacitor filter in output side. Then we get a maximum voltage of 2Vm.
Pkn said:
8 years ago
Answer should be 50.
Sankar said:
8 years ago
Yes, it is 50.
Mukund said:
8 years ago
No @Hari Charan.
The peak inverse voltage of half wave rectifier = Vm. So, the answer should be 50V.
The peak inverse voltage of half wave rectifier = Vm. So, the answer should be 50V.
(1)
Hari charan said:
9 years ago
PIV of the diode in HWR is 2 X VM.
2 X 50 = 100.
2 X 50 = 100.
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