Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 16 (Q.No. 15)
15.
In case of photo conductor for germanium when forbidden energy gap is 0.72 eV, the critical wavelength for intrinsic excitation will be
Discussion:
2 comments Page 1 of 1.
Amaresh dhani said:
7 years ago
&lamda; <=1.24/Eg micrometre.
1.24/.72=1.73 micrometre.
1.24/.72=1.73 micrometre.
Ajit said:
9 years ago
E = hc/lamda.
Lambda = hc/E.
= 6.625 * 10^-34 * 3 * 10^8/0.72 * 1.62 * 10^-19.
= 1.73 micro meter.
Lambda = hc/E.
= 6.625 * 10^-34 * 3 * 10^8/0.72 * 1.62 * 10^-19.
= 1.73 micro meter.
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