Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 1 (Q.No. 50)
50.
The minority carrier life time and diffusion constant in a semiconductor material are respectively 100 microsecond and 100 cm2/sec. The diffusion length is
Answer: Option
Explanation:
Diffusion length = 
.
Discussion:
7 comments Page 1 of 1.
Nabraj yadav said:
2 years ago
I think the given answer is correct.
Diffusion length = √(life time * diffusion constant).
Diffusion length = √(life time * diffusion constant).
Sean said:
5 years ago
√(100x10^-6 x 100)= 0.1cm.
(2)
Surekha said:
7 years ago
Explain in detail.
(1)
Sayan said:
8 years ago
L=(D.T)^1/2 [ D=The diffusion coefficient, L=diffusion length, T= specific life time).
Here T=100 Sec = 10^(-4) sec.
and D=100 cm^2/sec.
Now L=(10^2/ 10^4)^(1/2)= (1/10) = 0.1 cm.
Here T=100 Sec = 10^(-4) sec.
and D=100 cm^2/sec.
Now L=(10^2/ 10^4)^(1/2)= (1/10) = 0.1 cm.
(2)
Saleem said:
8 years ago
I think the answer is 1cm.
(1)
PRAKASH said:
10 years ago
(100*100)/1000000 = 1/100.
Under root of 1/100 1/10 = 0.1 cm.
Under root of 1/100 1/10 = 0.1 cm.
(2)
Thiru said:
1 decade ago
Please explain using formula?
(2)
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