Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 7 (Q.No. 10)
10.
Given that the band gap of cadmium sulphide is 2.5 eV, the maximum photon wavelength, for e--hole pair generation will be
Discussion:
3 comments Page 1 of 1.
Ajax said:
7 years ago
E = hf.
f = E/h = 2.5eV (1.6E-19J)/h.
λ = c/f = 5000 angstroms
Correct me if I'm wrong.
f = E/h = 2.5eV (1.6E-19J)/h.
λ = c/f = 5000 angstroms
Correct me if I'm wrong.
(1)
Mukund said:
8 years ago
can anyone explain how?
(1)
Priya said:
7 years ago
How?
(1)
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