Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 3 (Q.No. 4)
4.
The skin depth of copper is found to be 66 mm at 1 MHz at a certain temperature. At the same temperature and at 2 MHz, the skin depth would be approximately
Answer: Option
Explanation:
Skin depth = 
Discussion:
8 comments Page 1 of 1.
Mary Jane Malibiran said:
3 years ago
Get the conductivity first using the formula with skin depth= 66mm and w = 2π(1MHz). After getting the conductivity. Use the formula again, get the skin depth using w = 2π(2MHz). Then convert to meter.
Avinash said:
4 years ago
Can anyone explain with given formula?
Vasanth said:
6 years ago
S.D = 46.67 mm = 47 mm.
Azar said:
6 years ago
μ - Permeability = 4* 10^ -7 H/m.
σ - Conductivity in Mho/m or Siemens/m.
ω= 2*f.
f - frequency in Hz.
σ - Conductivity in Mho/m or Siemens/m.
ω= 2*f.
f - frequency in Hz.
Ajit said:
7 years ago
S1/S2 = square root (w2/w1),
66 mm/S2 = square root (2/1),
S2 = 66 mm/square root (2),
S2 = 46.67 mm = 47 μm.
66 mm/S2 = square root (2/1),
S2 = 66 mm/square root (2),
S2 = 46.67 mm = 47 μm.
Hari charan said:
7 years ago
Yes, by using a formula we get the answer as 47 μm.
Hari charan said:
7 years ago
@Kshama.
Please provide the Detailed explanation.
Please provide the Detailed explanation.
Kshama said:
7 years ago
Yes, the answer is 47 μm.
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