Electronics and Communication Engineering - Electronic Devices and Circuits
Exercise : Electronic Devices and Circuits - Section 12
- Electronic Devices and Circuits - Section 14
- Electronic Devices and Circuits - Section 27
- Electronic Devices and Circuits - Section 26
- Electronic Devices and Circuits - Section 25
- Electronic Devices and Circuits - Section 24
- Electronic Devices and Circuits - Section 23
- Electronic Devices and Circuits - Section 22
- Electronic Devices and Circuits - Section 21
- Electronic Devices and Circuits - Section 20
- Electronic Devices and Circuits - Section 19
- Electronic Devices and Circuits - Section 18
- Electronic Devices and Circuits - Section 17
- Electronic Devices and Circuits - Section 16
- Electronic Devices and Circuits - Section 15
- Electronic Devices and Circuits - Section 1
- Electronic Devices and Circuits - Section 13
- Electronic Devices and Circuits - Section 12
- Electronic Devices and Circuits - Section 11
- Electronic Devices and Circuits - Section 10
- Electronic Devices and Circuits - Section 9
- Electronic Devices and Circuits - Section 8
- Electronic Devices and Circuits - Section 7
- Electronic Devices and Circuits - Section 6
- Electronic Devices and Circuits - Section 5
- Electronic Devices and Circuits - Section 4
- Electronic Devices and Circuits - Section 3
- Electronic Devices and Circuits - Section 2
41.
The current in an RL series circuit is 1 - e-t amperes. Then di/dt is
Answer: Option
Explanation:
= 0 - (-e-t) = e-t.
42.
Given 
, and f(t)t → ∞ is 
. The value of k is
, and f(t)t → ∞ is . The value of k isAnswer: Option
Explanation:
.
43.
In a one port network 
. It is excited by a unit step current. The initial and final values of voltage across the network impedance are
. It is excited by a unit step current. The initial and final values of voltage across the network impedance are
1 and 0
Answer: Option
Explanation:
44.
In the circuit of figure, the current through battery E2 is
Answer: Option
Explanation:
1 A current is flowing into the battery. Therefore, it is charging current.
45.
In figure, the current supplied by battery at t = 0.5s is
Answer: Option
Explanation:
Time constant of R-L branch = 
= 0.5 seconds. Current in 6Ω resistance is 1 A and current in R-L branch is 63.2% of final current of 1 A.
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