Electronics and Communication Engineering - Electronic Devices and Circuits
Exercise : Electronic Devices and Circuits - Section 2
- Electronic Devices and Circuits - Section 14
- Electronic Devices and Circuits - Section 27
- Electronic Devices and Circuits - Section 26
- Electronic Devices and Circuits - Section 25
- Electronic Devices and Circuits - Section 24
- Electronic Devices and Circuits - Section 23
- Electronic Devices and Circuits - Section 22
- Electronic Devices and Circuits - Section 21
- Electronic Devices and Circuits - Section 20
- Electronic Devices and Circuits - Section 19
- Electronic Devices and Circuits - Section 18
- Electronic Devices and Circuits - Section 17
- Electronic Devices and Circuits - Section 16
- Electronic Devices and Circuits - Section 15
- Electronic Devices and Circuits - Section 1
- Electronic Devices and Circuits - Section 13
- Electronic Devices and Circuits - Section 12
- Electronic Devices and Circuits - Section 11
- Electronic Devices and Circuits - Section 10
- Electronic Devices and Circuits - Section 9
- Electronic Devices and Circuits - Section 8
- Electronic Devices and Circuits - Section 7
- Electronic Devices and Circuits - Section 6
- Electronic Devices and Circuits - Section 5
- Electronic Devices and Circuits - Section 4
- Electronic Devices and Circuits - Section 3
- Electronic Devices and Circuits - Section 2
36.
An RLC series circuit has Q = 100 and ω0 = 20 rad/sec. The bandwidth is
Answer: Option
Explanation:
37.
For making a capacitor, the dielectric should have
Answer: Option
Explanation:
A high ∈r will lead to high value of capacitance.
38.
In an unloaded transformer, the fluxes limiting the primary and secondary are 30 mWb and 20 mWb. The coefficient of coupling is
Answer: Option
Explanation:
Φ11 = (1 - k) Φ1 
φ11 = φ1 - φ2
30 - 20 10 mWb
10 mWb = (1 - k) 30m 0.33 = 1 - k k = 0.67 .
39.
Heat in calories = I2Rt/4.186.
Answer: Option
Explanation:
Calories and joules are related by mechanical equivalent of heat which is 4.186 .
40.
Poles and zeros of a driving point function of a network are simple and alternate on jω axis. The network consists of
Answer: Option
Explanation:
In network having only L and C, poles and zeros of driving point function are simple and alternate on jω axis.
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