Electronics and Communication Engineering - Electronic Devices and Circuits
Exercise : Electronic Devices and Circuits - Section 2
- Electronic Devices and Circuits - Section 14
- Electronic Devices and Circuits - Section 27
- Electronic Devices and Circuits - Section 26
- Electronic Devices and Circuits - Section 25
- Electronic Devices and Circuits - Section 24
- Electronic Devices and Circuits - Section 23
- Electronic Devices and Circuits - Section 22
- Electronic Devices and Circuits - Section 21
- Electronic Devices and Circuits - Section 20
- Electronic Devices and Circuits - Section 19
- Electronic Devices and Circuits - Section 18
- Electronic Devices and Circuits - Section 17
- Electronic Devices and Circuits - Section 16
- Electronic Devices and Circuits - Section 15
- Electronic Devices and Circuits - Section 1
- Electronic Devices and Circuits - Section 13
- Electronic Devices and Circuits - Section 12
- Electronic Devices and Circuits - Section 11
- Electronic Devices and Circuits - Section 10
- Electronic Devices and Circuits - Section 9
- Electronic Devices and Circuits - Section 8
- Electronic Devices and Circuits - Section 7
- Electronic Devices and Circuits - Section 6
- Electronic Devices and Circuits - Section 5
- Electronic Devices and Circuits - Section 4
- Electronic Devices and Circuits - Section 3
- Electronic Devices and Circuits - Section 2
16.
A capacitor used for power factor correction is single phase circuit decreases
Answer: Option
Explanation:
Capacitor is used to improve (increase) p.f. Therefore, line current is decreased for the same active power.
17.
Evaluate the value of 2 [u (t - 1) - u (1 - 2t)] (u ( t + 1) + u (t)) at t = 3 sec.
Answer: Option
Explanation:
2[u(2) - u(1 - 6)] [u(4) + u(3)] 
2 [1 - 0] [1 + 1] 4.
18.
Assertion (A): In an R-L circuit having high inductance, the rise of current is very slow.
Reason (R): The time constant of R-L circuit is L/R.
Answer: Option
Explanation:
A high value of time constant results in slow rise of current.
19.
The distance between the plates of a parallel plate capacitor is d. The dielectric is in two parts, each of equal thickness but dielectric constants ∈1 and ∈2 respectively. The total capacitance will be proportional to
∈1 - ∈2
∈1∈2
Answer: Option
Explanation:
The combination is equal to two capacitors in series.
Hence, 
.
20.
An air cored coil has an inductance of 0.3 H. If another coil has an iron core of μr = 500, the remaining quantities being the same, the inductance of the second coil will be
0.3 H
0.3 x 500 H
none of the above
Answer: Option
Explanation:
Inductance a μr.
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