Electronics and Communication Engineering - Electronic Devices and Circuits
Exercise : Electronic Devices and Circuits - Section 2
- Electronic Devices and Circuits - Section 14
- Electronic Devices and Circuits - Section 27
- Electronic Devices and Circuits - Section 26
- Electronic Devices and Circuits - Section 25
- Electronic Devices and Circuits - Section 24
- Electronic Devices and Circuits - Section 23
- Electronic Devices and Circuits - Section 22
- Electronic Devices and Circuits - Section 21
- Electronic Devices and Circuits - Section 20
- Electronic Devices and Circuits - Section 19
- Electronic Devices and Circuits - Section 18
- Electronic Devices and Circuits - Section 17
- Electronic Devices and Circuits - Section 16
- Electronic Devices and Circuits - Section 15
- Electronic Devices and Circuits - Section 1
- Electronic Devices and Circuits - Section 13
- Electronic Devices and Circuits - Section 12
- Electronic Devices and Circuits - Section 11
- Electronic Devices and Circuits - Section 10
- Electronic Devices and Circuits - Section 9
- Electronic Devices and Circuits - Section 8
- Electronic Devices and Circuits - Section 7
- Electronic Devices and Circuits - Section 6
- Electronic Devices and Circuits - Section 5
- Electronic Devices and Circuits - Section 4
- Electronic Devices and Circuits - Section 3
- Electronic Devices and Circuits - Section 2
6.
In the given circuit, viewed from AB, the circuit can be reduced to an equivalent circuit as


Answer: Option
Explanation:
For RTh, Voltage source will be short circuited RTh = 2.4 Ω,
VAB = 10 - 6 I 7 V.
7.
For the network of figure KVL for first loop is


Answer: Option
Explanation:
M term is negative because i1, is entering the dotted terminal and i2, is leaving the dotted terminal.
8.
An RC series circuit is charged by a voltage E. After a long time the battery is removed and a short circuit is placed across R-C. Then
Answer: Option
Explanation:
Direction of current during discharging is opposite to that during charging.
9.
Two coils having self inductances of 10 mH and 40 mH are mutually coupled. The maximum possible mutual inductance is
Answer: Option
Explanation:
Maximum mutual inductance = L1L2 = 20 mH.
10.
In the circuit shown in figure the current I of sinusoidal source is


Answer: Option
Explanation:
Currents in resistance and inductance are out of phase by 90°. Hence I = 122 + 162 = 20 A.
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