Electronics and Communication Engineering - Digital Electronics - Discussion

Discussion Forum : Digital Electronics - Section 3 (Q.No. 9)

Digital Electronics

If the ladder reference voltage is 2 V, then minimum comparator resolution required is

0.125 V

1.25 V

12.5 V

Answer: Option

Explanation:

Discussion:

15 comments Page 1 of 2.

Tarun said: 7 years ago

Resolution formula = Vref/2^n now minimum bit is 4 then 2/2^4=2/16=.125v.

TARUN UPADHYAY said: 5 years ago

Because comparator required minimum no.of bits are 4 so,
n=4.
Then 2/2^4.

Ammar said: 6 years ago

How do you know the minimum number of bits is 4? @Tarun.

(1)

Lokesh said: 9 years ago

For Ladder circuits, Resolution Q = Vref/(2^(n)).

KISHOR said: 8 years ago

Formula resolution= vref/ 2^n.

2/16 = 0.125.

Xyz said: 9 years ago

Someone, please explain how 1.875 come?

Dhurandhar said: 8 years ago

How 16 came? Explain.

Priti said: 9 years ago

How it comes 1.875?

Nikita said: 7 years ago

Yes, right @Tarun.

Rishi Ram Panth said: 8 years ago

How 16 comes out?

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