Electronics and Communication Engineering - Digital Electronics - Discussion

Discussion Forum : Digital Electronics - Section 3 (Q.No. 9)
9.
If the ladder reference voltage is 2 V, then minimum comparator resolution required is
0.125 V
1.25 V
12.5 V
0
Answer: Option
Explanation:

.

Discussion:
15 comments Page 1 of 2.

TARUN UPADHYAY said:   5 years ago
Because comparator required minimum no.of bits are 4 so,
n=4.
Then 2/2^4.

Ammar said:   6 years ago
How do you know the minimum number of bits is 4? @Tarun.
(1)

Mkarthik said:   7 years ago
Thanks @Tarun.

Nikita said:   7 years ago
Yes, right @Tarun.

Tarun said:   7 years ago
Resolution formula = Vref/2^n now minimum bit is 4 then 2/2^4=2/16=.125v.

Dhurandhar said:   8 years ago
How 16 came? Explain.

Rishi Ram Panth said:   8 years ago
How 16 comes out?

Neena said:   8 years ago
How 16 came?

KISHOR said:   8 years ago
Formula resolution= vref/ 2^n.

2/16 = 0.125.

Lokesh said:   9 years ago
For Ladder circuits, Resolution Q = Vref/(2^(n)).


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