Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 1 (Q.No. 31)
31.
Minimum number of 2-input NAND gates required to implement the function F = (x + y) (Z + W) is
Answer: Option
Explanation:
F = (x + y) (z + w) = xy.(z + w)
= xyz + xyw
= minimum no. of 2 input NAND gate.
Discussion:
14 comments Page 2 of 2.
Kruthi said:
9 years ago
We can replace 1 with double bar.
Shiavnjali said:
1 decade ago
Any one can explain in detail?
Mangesh said:
10 years ago
Why are we taking double bar?
Rajkumar said:
6 years ago
5 two input Nand gates.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers