Electronics and Communication Engineering - Digital Electronics - Discussion

Discussion Forum : Digital Electronics - Section 1 (Q.No. 31)
31.
Minimum number of 2-input NAND gates required to implement the function F = (x + y) (Z + W) is
3
4
5
6
Answer: Option
Explanation:

F = (x + y) (z + w) = xy.(z + w)

= xyz + xyw

= minimum no. of 2 input NAND gate.

Discussion:
14 comments Page 2 of 2.

Kruthi said:   9 years ago
We can replace 1 with double bar.

Shiavnjali said:   1 decade ago
Any one can explain in detail?

Mangesh said:   10 years ago
Why are we taking double bar?

Rajkumar said:   6 years ago
5 two input Nand gates.


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