Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 1 (Q.No. 31)
31.
Minimum number of 2-input NAND gates required to implement the function F = (x + y) (Z + W) is
Answer: Option
Explanation:
F = (x + y) (z + w) = xy.(z + w)
= xyz + xyw
= 
minimum no. of 2 input NAND gate.
Discussion:
14 comments Page 2 of 2.
Jaan said:
8 years ago
For implementing I think we should not alter the given Boolean equation and according to the procedure it requires 6 NAND gates.
Rajkumar said:
6 years ago
5 two input Nand gates.
Apoorva said:
6 years ago
Can someone explain the same problem with circuit concept?
Vraj said:
2 months ago
I think the answer is 6 then how the answer is 4? Anyone, please explain.
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