Electronics and Communication Engineering - Communication Systems - Discussion
Discussion Forum : Communication Systems - Section 3 (Q.No. 32)
32.
A noiseless 3 kHz channel can't transmit binary bit at the rate
Answer: Option
Explanation:
Noiseless channel: Nyquist's Theorem - If the signal has V discrete levels over a transmission medium of bandwidth H, the maximum data rate = 2H log2 V bits/sec.
A noiseless 3-kHz channel cannot transmit binary signals at a rate exceeding 6000 bps (= 2 x 3000 log2 2).
Discussion:
7 comments Page 1 of 1.
HUMAYUN KHAN said:
1 decade ago
I did not get this question? One HZ can carry 2 bits of information so I think 3kHz should carry 6 kHz, if not so then please clarify.
Vishaldeep said:
1 decade ago
Answer will be C.
log2 to base 2 = 1.
So 2*3000*1 = 6000 answer.
log2 to base 2 = 1.
So 2*3000*1 = 6000 answer.
Pkn said:
8 years ago
Yes, the answer is c.
Jai said:
8 years ago
Answer should be 6000bps.
Monika said:
7 years ago
@All.
Please note that, it is given (cannot transmit at what rate) So answer 1200 is right because at 6000 and below 6000 transmissions is possible but not above 60000.
Please note that, it is given (cannot transmit at what rate) So answer 1200 is right because at 6000 and below 6000 transmissions is possible but not above 60000.
Monika said:
7 years ago
12000 is the right answer. I agree.
Chandler said:
6 years ago
Well spotted @Monika.
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