Electronics and Communication Engineering - Analog Electronics - Discussion
Discussion Forum : Analog Electronics - Section 12 (Q.No. 43)
43.
A generator with an internal resistance of 600 Ω drives an amplifier whose input resistance is 400 Ω. The generator's open circuit voltages is 1 mV; the amplifier develops 100mV across an 8kΩ load. The current amplification is
Discussion:
1 comments Page 1 of 1.
Lasya said:
9 years ago
Current amplification Av = output current / input current.
Output current -> 100mv/8kohm - 12.5microamp.
Input current -> 1mv/1kohm - 1microamp.
Hence c/t amplification is 12.5.
Output current -> 100mv/8kohm - 12.5microamp.
Input current -> 1mv/1kohm - 1microamp.
Hence c/t amplification is 12.5.
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