Electronics and Communication Engineering - Analog Electronics - Discussion


A generator with an internal resistance of 600 Ω drives an amplifier whose input resistance is 400 Ω. The generator's open circuit voltages is 1 mV; the amplifier develops 100mV across an 8kΩ load. The current amplification is

[A]. 2.5
[B]. 12.5
[C]. 25
[D]. 125

Answer: Option B


No answer description available for this question.

Lasya said: (Aug 17, 2016)  
Current amplification Av = output current / input current.
Output current -> 100mv/8kohm - 12.5microamp.
Input current -> 1mv/1kohm - 1microamp.

Hence c/t amplification is 12.5.

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