Electronic Devices - Oscillator Circuits - Discussion
Discussion Forum : Oscillator Circuits - General Questions (Q.No. 9)
9.
Given gm = 5000 
S, rd = 40 k
, R = 10 k, and A = 35. Determine the value of RD for oscillator operation at 1 kHz.
S, rd = 40 k, R = 10 k, and A = 35. Determine the value of RD for oscillator operation at 1 kHz. 
8.05 k
8.48 k
10.8 k
12.3 k
Discussion:
5 comments Page 1 of 1.
Gennie said:
7 years ago
For FET, we have the equation Av=gm*Zo and Zo=RD//rd.
Combining these two equations, we would get Av=gm*[(RD*rd)/(RD+rd)].
35=5000uS * [(RD * 40kΩ)/(RD+40kΩ)].
RD = 8484.848Ω.
Combining these two equations, we would get Av=gm*[(RD*rd)/(RD+rd)].
35=5000uS * [(RD * 40kΩ)/(RD+40kΩ)].
RD = 8484.848Ω.
(6)
Thabiso said:
7 years ago
Please explain the answer clearly.
(1)
Nabi said:
7 years ago
Please explain it clearly.
Aditi said:
8 years ago
Please explain in detail.
Shanky said:
1 decade ago
As mod of gain, A = gm*Rl.
RL = RD * rd/RD +rd.
So we get the answer.
RL = RD * rd/RD +rd.
So we get the answer.
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