Electronic Devices - Oscillator Circuits - Discussion

Discussion Forum : Oscillator Circuits - General Questions (Q.No. 7)
7.

Refer to this figure. Determine the resonant frequency.

123.4 kHz
61.7 kHz
45.94 kHz
23.1 kHz
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
12 comments Page 1 of 2.

Ravi said:   9 years ago
F = 1/{2φsqrt(C (L1 + L2 ))}.
F = 1/{2 x 3.14 sqrt((200 x 10 - 9)(60 x 10 - 3)}.
F = 1/{2 x 3.14 sqrt(12 x 10 - 9)}.
F = 1/{2 x 3.14 x 3.46 x 10 - 3}.
F = 1/{21.75 x 10 - 3}.
F = 45.97.

Ajay said:   1 decade ago
F = 2 x 3.14 sqrt((200 x 10-9)(60 x 10-3).

Please more explain is square root, 10-9 and 10-3.

EPB said:   1 year ago
fr = 1/[2π*√(L*C)].
fr = 1/[(2*π)(√((60x10^-3)(200x10^-12)))].

Raver said:   5 years ago
I thought the two inductors were in parallel due to ground :( .
(2)

Vikas0492 said:   9 years ago
@Ravi.

How 10-9 and 10-3 came? Please explain.

Jeremy Tumazar said:   1 year ago
L(eq)= L1+L2+2M.
where M=k(√(L1*L2).

Sneha said:   9 years ago
@Vikas0492.

Pico 10^-9.
Milli 10^-3.

Raz said:   1 decade ago
f = 2*3.14sqrt((200*10-9)(60*10-3)).

Hima said:   1 decade ago
F = 1 / 2πsqrt(C (L1 + L2 ))

Tiara said:   1 decade ago
Method to solve this?


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