Electronic Devices - Oscillator Circuits - Discussion
Discussion Forum : Oscillator Circuits - General Questions (Q.No. 7)
7.
Refer to this figure. Determine the resonant frequency.
Discussion:
12 comments Page 1 of 2.
Jeremy Tumazar said:
1 year ago
L(eq)= L1+L2+2M.
where M=k(√(L1*L2).
where M=k(√(L1*L2).
EPB said:
1 year ago
fr = 1/[2π*√(L*C)].
fr = 1/[(2*π)(√((60x10^-3)(200x10^-12)))].
fr = 1/[(2*π)(√((60x10^-3)(200x10^-12)))].
Raver said:
5 years ago
I thought the two inductors were in parallel due to ground :( .
(2)
Behan said:
9 years ago
@Sneha.
Pico 10^-12.
Pico 10^-12.
Sneha said:
9 years ago
@Vikas0492.
Pico 10^-9.
Milli 10^-3.
Pico 10^-9.
Milli 10^-3.
Vikas0492 said:
9 years ago
@Ravi.
How 10-9 and 10-3 came? Please explain.
How 10-9 and 10-3 came? Please explain.
Ravi said:
9 years ago
F = 1/{2φsqrt(C (L1 + L2 ))}.
F = 1/{2 x 3.14 sqrt((200 x 10 - 9)(60 x 10 - 3)}.
F = 1/{2 x 3.14 sqrt(12 x 10 - 9)}.
F = 1/{2 x 3.14 x 3.46 x 10 - 3}.
F = 1/{21.75 x 10 - 3}.
F = 45.97.
F = 1/{2 x 3.14 sqrt((200 x 10 - 9)(60 x 10 - 3)}.
F = 1/{2 x 3.14 sqrt(12 x 10 - 9)}.
F = 1/{2 x 3.14 x 3.46 x 10 - 3}.
F = 1/{21.75 x 10 - 3}.
F = 45.97.
Ajay said:
1 decade ago
F = 2 x 3.14 sqrt((200 x 10-9)(60 x 10-3).
Please more explain is square root, 10-9 and 10-3.
Please more explain is square root, 10-9 and 10-3.
Ajay said:
1 decade ago
Please solve answer.
Raz said:
1 decade ago
f = 2*3.14sqrt((200*10-9)(60*10-3)).
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