Electronic Devices - Op-Amp Applications - Discussion
Discussion Forum : Op-Amp Applications - General Questions (Q.No. 2)
2.
Calculate the output voltage if V1 = –0.2 V and V2 = 0 V.
Discussion:
13 comments Page 2 of 2.
Mallik said:
1 decade ago
As the figure shows.. op-amp used here is inverting amplifier. From the circuit configuration we can conclude that it is an adder , where inputs are given to inverting port. the formula goes in the following way..
Vout = -[{(V1/R1)+(V2/R2)}/{(1/Rf)}]
Here V1= -0.2v; V2= 0v R1= 33k; R2=10k ; Rf=330k
=> Vout = -[(V1/R1)*Rf]
Vout= -[V1*(330k/33k)]
Vout = -[-0.2*10]
Vout = 2v
Vout = -[{(V1/R1)+(V2/R2)}/{(1/Rf)}]
Here V1= -0.2v; V2= 0v R1= 33k; R2=10k ; Rf=330k
=> Vout = -[(V1/R1)*Rf]
Vout= -[V1*(330k/33k)]
Vout = -[-0.2*10]
Vout = 2v
Vandana said:
1 decade ago
It is not a non inverting amplifier, it is an simple inverting amplifier. If it is a non inverting amplifier then formula for voltage output should be diffrent.
Amit bhattacharya said:
1 decade ago
As v2 is zero so that branch can be neglected
i.e. 10k can be neglected
Now the circuit is simple non inverting amp
and v0=(-Rf/R1)*v1
=-(330k/33k)*(-0.2)
=2v
i.e. 10k can be neglected
Now the circuit is simple non inverting amp
and v0=(-Rf/R1)*v1
=-(330k/33k)*(-0.2)
=2v
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