Electronic Devices - Diode Applications - Discussion
Discussion Forum : Diode Applications - General Questions (Q.No. 1)
1.
Determine the total discharge time for the capacitor in a clamper having C = 0.01 
F and R = 500 k
.
F and R = 500 k.Discussion:
21 comments Page 1 of 3.
Gangadhar reddy said:
1 decade ago
Yes, the answer is correct because we take 5 time constants in practical so the formula is 5*R*C.
(1)
Santosh aladakatti said:
1 decade ago
Discharging time t=5rc.
So ans=25ms.
So ans=25ms.
(1)
DINESH said:
1 decade ago
Actually there are two responses one is transient response and steady state response steady state response occurs after the output becomes constant so it is almost equal to transient response so the answer is 5*RC.
(1)
Vijay Shinde said:
1 decade ago
The discharge voltage for the capacitor is given by:
VC (t) = Vo exp(-t/RC) for t > or = 0
Here, t exp(-t/RC)
t=1*RC 0.37
t=2*RC 0.14
t=3*RC 0.05
t=4*RC 0.02
t=5*RC 0.01
So that practically we say that after 5 time constant capacitor is fully charged/Discharged.
VC (t) = Vo exp(-t/RC) for t > or = 0
Here, t exp(-t/RC)
t=1*RC 0.37
t=2*RC 0.14
t=3*RC 0.05
t=4*RC 0.02
t=5*RC 0.01
So that practically we say that after 5 time constant capacitor is fully charged/Discharged.
Mahun Mughal said:
6 years ago
A Rectifier convert the AC into DC using the Converter method.
Neha said:
9 years ago
@Mughil.
Which convert AC power supply to DC power supply?
Which convert AC power supply to DC power supply?
Mughil said:
10 years ago
Convert Ac signal to Dc signal.
Divya said:
1 decade ago
To convert AC to pulsating DC.
Sumit said:
1 decade ago
To convert ac in dc.
Babar pervez said:
1 decade ago
Q1: Why we use rectifier?
Q2: What is the purpose of rectifier?
Q2: What is the purpose of rectifier?
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